Consider the following radioactive decay process
${ }_{84}^{218} A \stackrel{\alpha}{\longrightarrow} A_1 \stackrel{\beta^{-}}{\longrightarrow} A_2 \stackrel{\gamma}{\longrightarrow} A_3 \stackrel{\alpha}{\longrightarrow} A_4 \stackrel{B^{+}}{\longrightarrow} A_5 \stackrel{\gamma}{\longrightarrow} A_6$
The mass number and the atomic number $A _6$ are given by
$210$ and $82$
$210$ and $84$
$210$ and $80$
$211$ and $80$
During a negative beta decay
A nucleus of atomic mass $A$ and atomic number $Z$ emits ${M_1}$ particles. The atomic mass and atomic number of the resulting nucleus are
${ }_{82}^{290} X \xrightarrow{\alpha} Y \xrightarrow{e^{+}} Z \xrightarrow{\beta^{-}} P \xrightarrow{e^{-}} Q$
In the nuclear emission stated above, the mass number and atomic number of the product $Q$ respectively, are
${ }_{92}^{238} U$ atom disintegrates to ${ }_{84}^{214} Po$ with a half of $45 \times 10^9$ years by emitting $\operatorname{six} \alpha-$ particles and $n$ electrons. Here, $n$ is
A certain stable nucleide, after absorbing a neutron, emits $\beta$-particle and the new nucleide splits spontaneously into two $\alpha$-particles. The nucleide is